On Tue, Jul 29, 2025 at 04:42:13PM -0700, Alan Grayson wrote:

Eigenvectors of a hermitian operator are orthogonal (or can be
trivially orthogonalised in the case of multiple linearly independent
eignvectors with the same eigenvalue).

> 
> What does "true by construction" mean? Does that include orthogonality of the
> basis eigenstates? AGĀ 
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