On Sat, 18 Oct 2025 at 20:25, gene heskett <[email protected]> wrote:
> I have about half the code written & to implement the results, so the > question is: which of the G10 codes is the equ of a touch off for the > named axis's? There are two ways to do this. The simplest is probably to calculate your centre point, move to that point, and then. G10 L20 X0 Y0 Or you could calculate the position of the centre in _machine_ coordinates and then set the offset directly with G10 L2. (To probe in machine coordinate space you could zero the current offset with G10 L2 X0 Y0) As you probably want to go to the centre anyway, I would advocate the simpler G10 L20 way. -- atp "A motorcycle is a bicycle with a pandemonium attachment and is designed for the especial use of mechanical geniuses, daredevils and lunatics." — George Fitch, Atlanta Constitution Newspaper, 1912 _______________________________________________ Emc-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/emc-users
