Jonathan Leech-Pepin <jonathan.leechpe...@gmail.com> writes: > I'm not sure as to the reason why it does so, but based on your > example, the formula is referencing the specific cell itself, rather > than the relative position of the cell. If you change your formula to > use a relative reference, it will continue to work even when you add, > remove and move the rows. > > #+TBLFM: @2$3..@>$3=vmean(@I$2..@0$2);%.1f > or > #+TBLFM: @2$3..@>$3=vmean(@<<$2..@0$2);%.1f > will both provide you with the result you seem to be looking for. The > former uses your (first) horizontal line as the starting point, > whereas the latter uses the 2nd row from the top. > > Regards, > Jonathan > > On Thu, Dec 1, 2011 at 12:42, henry atting <nsmp...@online.de> wrote: > > Suppose I have this table: > > | month | expenses | average | > |-------+----------+---------| > | 1 | 20 | | > | 2 | 30 | 25.0 | > | 3 | 40 | 30.0 | > #+TBLFM: @3$3..@>$3=vmean(@2$2..@0$2);%.1f > > Then I want to delete the second row and add a new one at the > bottom. > If I do so I get `#ERROR' on every recalculation. > > | month | expenses | average | > |-------+----------+---------| > | 2 | 30 | #ERROR | > | 3 | 40 | #ERROR | > | 4 | 50 | #ERROR | > #+TBLFM: @2$3..@>$3=vmean(@INVALID$2..@0$2);%.1f > > If I push the second row to the bottom the > result is as if the last row is still the second one. > > | month | expenses | average | > |-------+----------+---------| > | 2 | 30 | 30.0 | > | 3 | 40 | 30.0 | > | 1 | 20 | 20.0 | > #+TBLFM: @2$3..@>$3=vmean(@4$2..@0$2);%.1f >
Ah, I see the problem; and thanks, it works fine now. henry -- http://literaturlatenight.de
