On Wed, Aug 17, 2011 at 3:35 AM, Nick Dokos <nicholas.do...@hp.com> wrote:
> Matt Price <mopto...@gmail.com> wrote: > > > Hi, > > > > It's htat time of year again and I'm putting together course syllabi. I > would really love to be able > > to dynamically calculate dates in a spreadsheet, e.g.: > > > > |Topic 1|Date1|Description1| > > |Topic2|Above Date + 7| Description2| > > |Topic3|Above Date + 7| Description3| > > > > Is there a way for me to do that? > > As usual in situations like this, you have to start things off with > a field formula for the first date. The column formula then can be > used to calculate all the *other* rows (field formulas override column > formulas - see section 3.5.6, "Column formulas", in the org manual > or evaluate (info "(org) Column formulas") to get there directly). > > | Topic 1 | <2011-08-17 Wed> | Description1 | > | Topic2 | <2011-08-24 Wed> | Description2 | > | Topic3 | <2011-08-31 Wed> | Description3 | > #+TBLFM: @1$2=<2011-08-17> :: $2 = <@-1$2> + 7 > > The column formula says: get the field from the row above and the same > column (@-1$2), interpret it as a date (<..>) and add 7 (days) to it. > The column formula can be simplified to $2 = <@-1> + 7. > > If you want to increment by e.g. 10 mins, the increment has to be > calculated as a fraction of a day: > > | Topic 1 | <2011-09-18 Sun 10:20> | Description1 | > | Topic2 | <2011-09-18 Sun 10:30> | Description2 | > | Topic3 | <2011-09-18 Sun 10:40> | Description3 | > #+TBLFM: @1$2=<2011-09-18 10:20> :: $2 = <@-1> + 10*(1/24*60)) > > > ah, supercool. thank you!! matt
