Hi, I've been looking through the manual to get more familiar with Babel and using source code in general. Below is a simple example, which I'm not sure is working as intended.
#+tblname: example-table | 1 | a | | 2 | b | | 3 | c | | 4 | d | #+begin_src emacs-lisp :var data=example-table[-3,1] :results value raw data #+end_src Upon =C-c C-c= this produces the expected result: #+results: b =C-c C-c= /again/, however, results in: #+results: b b In other words, the default results handling of =replace= appears to not work with a =raw= results type. I tried explicitly adding the handling via a =:results value raw replace= header argument but again this didn't seem to fix things. Is this what is intended for the =raw= type of results - no replacement effect at all - or is this a bug? Chris
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