Looking at ob-calc there is a call to calc-push-list. Knowing the length of that list (i.e. the number of arguments) it should be possible to inspect calc-stack to retrieve the other values on the stack from the current block. You can see this if you run M-: calc-stack. This would probably need a specialized result type if it were implemented. Best, Tom
On Wed, May 5, 2021 at 8:33 AM <pie...@caramail.com> wrote: > > > Example > > (require 'ob-calc) > (org-babel-do-load-languages > 'org-babel-load-languages > '( (calc . t) ) > > -------- calc.org -------- > > # To execute, place cursor point on a line, then hit "C-c * u" hard with no > harm. > > #+name: Simplifying Formulas > #+begin_src calc > > simplify((x + y) (x + y)) => > > simplify(a x^2 b / (c x^3 d)) => > > simplify((4 x + 6) / (8 x)) => > > simplify((1 + 2 i) (3 + 4 i)) => > > simplify(5 + i^2 + i - 8 i) => > > simplify((1, 2) + (3, 4)) => > > simplify((1, 2) (3, 4)) => > > #+end_src > > > > Sent: Thursday, May 06, 2021 at 3:11 AM > From: "Matt Price" <mopto...@gmail.com> > To: "Org Mode List" <emacs-orgmode@gnu.org> > Cc: pie...@caramail.com > Subject: Re: Multiple calc commands with orgbabel > Can you explain how you get calc embedded mode working in org? I have never > used it and it sounds interesting, but I don't understand what hte delimiters > are. > > On Wed, May 5, 2021 at 2:35 AM Eric S Fraga <e.fr...@ucl.ac.uk> wrote: >> >> On Wednesday, 5 May 2021 at 07:46, pie...@caramail.com wrote: >> > Have been trying to execute multiple calc commands, but when I >> > evaluate the calc expressions, I get just one result. >> >> ob-calc returns the top element of the stack when finished and this will >> be the result of the last operation in the src block. I don't think >> there's any way around this. >> >> I use embedded Calc for this reason. You could rewrite your equations >> as simple lines (separated by empty lines from the surroundings) and >> evaluate each in turn with "C-x * u": >> >> fsolve(x 2 + x = 4, x) => x = 1.33333333333 >> >> fsolve([x + y = a, x - y = b], [x, y]) => [x = a + (b - a) / 2, y = (a - b) >> / 2] >> >> I added the "=>" at the end of each expression so that the result is >> shown to the right instead of replacing the expression itself (default >> embedded Calc behaviour). >> >> -- >> : Eric S Fraga via Emacs 28.0.50, Org release_9.4.5-395-g82fbdd >>
