I had a read of that, is good but seems overly basic for what I'm
trying to achieve.

Basically a list of links like so on the Template:

Link: Cards 0-50
Link: Cards 51-100
Link: Cards 101-132

Know what I mean?
My biggest question being, how can I create that above list with the
data I have, basically the record count "132".



d



On Oct 11, 7:41 pm, Daniel Roseman <dan...@roseman.org.uk> wrote:
> On Oct 11, 9:22 am, The Danny Bos <danny...@gmail.com> wrote:
>
>
>
>
>
> > Heya, thanks for all the help of late, I'm about four late nights from
> > finishing my first big app I'm guessing.
>
> > Anyway,
> > I'm working on paging in my app and am completely stuck (again),
> > here's what I'm trying for:
> >          eg:http://www.domainname.com/card/pokemon/0-50/
>
> > Which would obviously display a list of 'Pokemon' cards from numbers 0
> > to 50.
>
> > To get those numbers from the URL, I'm doing:
> >         paging = str(paging)
> >         paging = paging.split("-")
> >         page_from = paging[0]
> >         page_to = paging[1]
> >         items = Cards.objects.all()[page_from:page_to]
>
> > Seems to work but may need some error checking, yeh?
>
> > Where I'm really stuck is listing out the pages in the template like
> > so:
> >          <a href="">0-50</a>, <a href="">51-100</a>, <a href="">101-132</a>.
>
> > I guess I need to get the Count of the records first, in this case
> > "132". Then how would I loop through and create those links
> > automatically. As each Card set may be different obviously, some may
> > have "43" records, some "682" records etc ... But I still want to page
> > through by "50" each time using the URL.
>
> > Any help would be great, I'm really stumped on this one.
> > Hope that's enough info to get some help.
>
> > d
>
> There is a whole section of the documentation devoted to 
> pagination:http://docs.djangoproject.com/en/dev/topics/pagination/
> including some useful built-in functionality.
> --
> DR.
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