Thank you very much. I think i get the idea.

Greetings
Sven

On Tue, Aug 25, 2009 at 10:51 PM, Peter Bengtsson <pete...@gmail.com> wrote:

>
> I fear your only option is to write a recursive function which you
> feed with what you define to be "the end of the chain".
> You can collect all the entries in a mutable list. Some example,
> untested, code:
>
> def get_all_parents(list_, current):
>    for entry in current.following_to.all():
>        list_.append(entry)
>        list_.extend(get_all_parents(list_, entry)
>    return list_
>
> current = A
> parents = []
> get_all_parents(parents, current)
> print parents
>
> Excuse me if I didn't get it right but it should get you started.
>
> On Aug 25, 10:11 am, Sven Richter <sver...@googlemail.com> wrote:
> > Hi,
> >
> > i implemented a many-to-many field in my model like:
> > class Entries(models.Model):
> >   following_to = models.ManyToManyField('self', blank=True, null=True)
> >
> > Now i can get all related Entries in a template with
> entry.following_to.all.
> > But i want to go deeper in relationships.
> >
> > Lets say i have 4 Entries A, B, C, D.
> > A is following_to to B and
> > B is following_to to C and
> > C is following_to to D.
> > A.following_to.all gives back B.
> >
> > But what i need is to follow until the end of the chain is reached.
> > I need something like:
> > A.following_to.give_all_related_entries which then returns:
> > B, C, D
> >
> > Do i have to write my own template tag for that or is it already
> implemented
> > in Django?
> > Or maybe there is a better approach to solve my issue?
> >
> > I couldnt find a similar question or answer in the docs.
> >
> > Greetings
> > Sven
> >
>

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