Thanks very much, it works now!
On Mar 24, 10:57 pm, Daniel Roseman <roseman.dan...@googlemail.com>
wrote:
> On Mar 24, 2:25 pm, SamuelXiao <foolsmart2...@gmail.com> wrote:
>
>
>
> > I am writing a simple application which takes parameter from the url
> > and simply put it to another python app and open it. If it is
> > successful, a content of the author's blog post will be returned.
> > The following is my code:
> > ----------This one works------------
> > #Using Django v1.02
> > #this function works well, no problem
> > #work in local server
> > #I simply callhttp://127.0.0.1:8000/mywiki/blog/getEntry.py
> > def getEntry(req,):
> > URL =
> > 'http://id:passw...@www.myschool.edu/CSserver/getPost.py?
> > author=50898712'
> > urlread=urllib.urlopen(URL).read()
> > entry = handleXMLPost(urlread)
> > return render_to_response('testsample.html',{"entry":entry})
>
> > ----------------This one not
> > works-------------------------------------
> > #this function not work, why?
> > #I simply callhttp://127.0.0.1:8000/mywiki/blog/getEntry.py?author=50898712
> > def getEntry(req,**kwargs):
> > stdid=kwargs['author']
> > URL =
> > 'http://id:passw...@www.myschool.edu/CSservergetPost.py?author=
> > %s' % stdid
> > urlread=urllib.urlopen(URL).read()
> > entry = handleXMLPost(urlread)
> > return render_to_response('testsample.html',{"entry":entry})
>
> > And Django debugger tells that :
> > ----------------------------------------------
> > KeyError at /mywiki/blog/getEntry.py
> > author
>
> > Request Method: GET
> > Request URL: http://127.0.0.1:8000/mywiki/blog/getEntry.py
> > Exception Type: KeyError
> > Exception Value: author
> > ....
> > ....
> > value of author :
> > u'50898712'
>
> > Does anyone know what is wrong with my function? Any help would be
> > appreciated.
>
> It doesn't work because Django doesn't pass in querystring parameters
> as kwargs to the view function.
> Instead, use request.GET['author'] to get the author variable from the
> request.
>
> --
> DR.
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