On Mar 24, 2:25 pm, SamuelXiao <foolsmart2...@gmail.com> wrote:
> I am writing a simple application which takes parameter from the url
> and simply put it to another python app and open it. If it is
> successful, a content of the author's blog post will be returned.
> The following is my code:
> ----------This one works------------
> #Using Django v1.02
> #this function works well, no problem
> #work in local server
> #I simply callhttp://127.0.0.1:8000/mywiki/blog/getEntry.py
> def getEntry(req,):
> URL =
> 'http://id:passw...@www.myschool.edu/CSserver/getPost.py?
> author=50898712'
> urlread=urllib.urlopen(URL).read()
> entry = handleXMLPost(urlread)
> return render_to_response('testsample.html',{"entry":entry})
>
> ----------------This one not
> works-------------------------------------
> #this function not work, why?
> #I simply callhttp://127.0.0.1:8000/mywiki/blog/getEntry.py?author=50898712
> def getEntry(req,**kwargs):
> stdid=kwargs['author']
> URL =
> 'http://id:passw...@www.myschool.edu/CSservergetPost.py?author=
> %s' % stdid
> urlread=urllib.urlopen(URL).read()
> entry = handleXMLPost(urlread)
> return render_to_response('testsample.html',{"entry":entry})
>
> And Django debugger tells that :
> ----------------------------------------------
> KeyError at /mywiki/blog/getEntry.py
> author
>
> Request Method: GET
> Request URL: http://127.0.0.1:8000/mywiki/blog/getEntry.py
> Exception Type: KeyError
> Exception Value: author
> ....
> ....
> value of author :
> u'50898712'
>
> Does anyone know what is wrong with my function? Any help would be
> appreciated.
It doesn't work because Django doesn't pass in querystring parameters
as kwargs to the view function.
Instead, use request.GET['author'] to get the author variable from the
request.
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DR.
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