On Tue, 2009-01-27 at 16:48 +0100, felix wrote: > > there is some hashing function or combination of URL encoding that can > do this : > > > given some parameters : > > 'music' 'artist' 32L 2L 100 100 > ( artist id 32, 2nd picture, dimensions 100 x 100 ) > > I wish to generate a fake filename eg: > > tartan_ba6e5e06e794f1368ed3ec20b4594eec.png > > and then be able to reverse that filename back into the original > parameters when needed. > > so its either hashing, or compressing the string (to use the most of > the allowable chars a-zA-Z0-9_ ) or something
Hashing is a one-way operation. You can go one way, but not the other. Why not just do something simple, like putting all the pieces into a string separated by something like commas? ','.join(parameters), for example? In fact, to work around problems with the separator appearing in the parameters themselves, I'd use something like django.utils.http.urlquote() to convert each parameter and then join them together with '&' (which urlquote will have encoding from the input parameters). The reverse process is then splitting on '&' and then calling urllib.unquote() on the parameters. Regards, Malcolm --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
