P.S ,,, Never use index in name generation, or you will run out of range one day ;) think of that nightmare in advance... i can only wish further schlaf süß, grüß Puneet
On Tue, Jan 27, 2009 at 10:25 PM, felix <crucialfe...@gmail.com> wrote: > > ah, danke dir ! > > that's exactly what I was looking for > > full encodings here: > http://docs.python.org/library/codecs.html#standard-encodings > > actually I guess in this case I would have a series of numbers; > > [ content_type_id, object_id, index, width, height ] > > rather than a string. I can figure that out, or it would be simple enough > to join them and do the pack. > it won't be so long as the example I posted. > > > FYI > this would be for thumbnails : if the thumbnail exists the static server > will serve it, else django will be triggered to build it. > > but I wouldn't want to open up the URL so that anybody could request say > > for i in range(0,10000): > get image urls until my server gives up ... > > > but I will design the paths so that it exposes the object ID like so: > > %(content_type_id)s_%(object_id)s_%(encoded)s.jpg > > so that I can easily delete all thumbs when the object is deleted > > currently I create thumbs on demand via template tags. > this also leaves dead thumbs laying around. > > > > > > On Tue, Jan 27, 2009 at 5:43 PM, Puneet Madaan <puneetmad...@gmail.com>wrote: > >> I am assuming that you already have an idea of how your datastring will >> look like, and what data it is containing... I am considering *"music >> artist 32L 2L 100 100"* as input data >> so here is a example... >> >> L1 = "music artist 32L 2L 100 100".encode("hex") >>> L2 = zlib.compress(L1) >>> L3 = L2.encode("hex") >>> print L3 >>> >> >> L3 can now be taken as URI referencing string.. which in this special case >> is >> >> >> '789c35c5c10d00200c02c095102aa4f3e8fe336862fcdc7967466e8bf00853ee28454862adfb7308c2ff00401d0b64' >> >> and reverse algo for this is also as easy >> >> >>> D1=789c35c5c10d00200c02c095102aa4f3e8fe336862fcdc7967466e8bf00853ee28454862adfb7308c2ff00401d0b64'.decode("hex") >>> D2 = zlib.decompress(D1) >>> D3 = D2.decode("hex") >>> >> >> you will get your "music artist 32L 2L 100 100" back >> >> And your URL will not send further a psuedo encoded number which is ugly >> enough for non-developers :D >> you are free to choose encoding, and can nest them in multiple algos to >> make the thing more complex >> >> greetings, >> Puneet >> >> >> On Tue, Jan 27, 2009 at 4:48 PM, felix <crucialfe...@gmail.com> wrote: >> >>> >>> there is some hashing function or combination of URL encoding that can do >>> this : >>> >>> >>> given some parameters : >>> >>> 'music' 'artist' 32L 2L 100 100 >>> ( artist id 32, 2nd picture, dimensions 100 x 100 ) >>> >>> I wish to generate a fake filename eg: >>> >>> tartan_ba6e5e06e794f1368ed3ec20b4594eec.png >>> >>> and then be able to reverse that filename back into the original >>> parameters when needed. >>> >>> so its either hashing, or compressing the string (to use the most of the >>> allowable chars a-zA-Z0-9_ ) or something >>> >>> hints or pointers anyone ? >>> thanks >>> >>> >>> >>> http://crucial-systems.com >>> >>> >>> >>> >> >> >> -- >> If you spin an oriental man, does he become disoriented? >> (-: ¿ʇɥǝɹpɹǝʌ ɟdoʞ uǝp ɹıp ɥɔı ,qɐɥ 'ɐɐu >> >> is der net süß » ε(●̮̮̃•̃)з >> -----PM >> >> >> > > > > -- If you spin an oriental man, does he become disoriented? (-: ¿ʇɥǝɹpɹǝʌ ɟdoʞ uǝp ɹıp ɥɔı ,qɐɥ 'ɐɐu is der net süß » ε(●̮̮̃•̃)з -----PM --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
