Hi Malcolm i am very new bie of Django. i read through
get_absolute_url but do not know how to use.
What you have given the answer i tried with that and its working fine
but my senior asked me what will happen if i change the site name then
every where you will have to change url
mysite.library.views.listing_view.
so they told me to use get_absolute_url
i wrote get_absolute_ul in models.py
def get_absolute_url(self):
return "/listing/%i/" % self.id
and i am trying to use in my html page template but i don't know how
to use
<li> <a href="{{get_absolute_url}}{{n.id}}">{{n.list_channel}}</a></
li>
then again same problem. first time when some one click on link it
works fine but second time it appends the link like
http://127.0.0.1:8000/category/listing_view/3/3
Please give me some idea
On Jan 8, 3:37 pm, Praveen <praveen.python.pl...@gmail.com> wrote:
> Thank you so much Malcolm.
> every one gives only the link and tell to read but your style of
> solving the problem is amazing. how you explained me in a nice way
> that i can never ever find in djangoproject.com.
> Thanks you so much malcom
>
> On Jan 8, 3:23 pm, Malcolm Tredinnick <malc...@pointy-stick.com>
> wrote:
>
>
>
> > I'm going to trim your code to what looks like the relevant portion of
> > the HTML template, since that's where the easiest solution lies.
>
> > On Thu, 2009-01-08 at 02:02 -0800, Praveen wrote:
>
> > [...]
>
> > > list_listing.html
>
> > > <div id="leftpart">
> > > <h3>Sight Seeings</h3>
> > > <ul>
> > > {%if listing_result %}
> > > {% for n in listing_result %}
> > > <li><a href="{{n.id}}">{{n.list_channel}}</a></li>
> > > {% endfor %}
> > > {% else %}
> > > <p>not available</p>
> > > {% endif %}
> > > </ul>
> > > </div>
>
> > [...]
>
> > > I am displaying Listing_channels and Listing on same page. if some one
> > > click on any Listing_channels the corresponding Listing must display
> > > on same page. that is why i am also sending the Listing_channels
> > > object to list_listing.html page. if some one click first time on
> > > Listing_channels it shows the
> > > urlhttp://127.0.0.1:8000/category/listing_view/1/
> > > but second time it appends 1 at the end and the url becomes
> > >http://127.0.0.1:8000/category/listing_view/1/1
>
> > The above code fragment is putting an element in the template that looks
> > like
>
> > <a href="1">...</a>
>
> > That is a relative URL reference and will be relative to the URL of the
> > current page (which is .../category/listing_view/1/). In other words, it
> > will be appended to that URL. One solution is to change the relative
> > reference to look like
>
> > <a href="../1">...</a>
>
> > or, in template language:
>
> > <li><a href="../{{n.id}}">{{n.list_channel}}</a></li>
>
> > That assumes you will only be displaying this template
> > as ..../listing_view/1/ (or with a different number as the final
> > component), since it will *always* remove the final component and
> > replace it with the id value.
>
> > The alternative, which is a little less fragile, is to use the "url"
> > template tag to include a URL that goes all the way back to the hostname
> > portion. You could write
>
> > <li><a href="
> > {% url mysite.library.views.listing_view n.id %}
> > ">{{n.list_channel}}</a></li>
>
> > (I've put in some line breaks just to avoid unpleasant line-wrapping).
> > The {% url ... %} portion will return "/category/listing_view/1/" -- or
> > whatever the right n.id value is -- which will always be correct.
>
> > Have a read
> > ofhttp://docs.djangoproject.com/en/dev/ref/templates/builtins/#urlif
> > you're not familiar with the URL tag.
>
> > Regards,
> > Malcolm
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