Thank you so much Malcolm.
every one gives only the link and tell to read but your style of
solving the problem is amazing. how you explained me in a nice way
that i can never ever find in djangoproject.com.
Thanks you so much malcom
On Jan 8, 3:23 pm, Malcolm Tredinnick <malc...@pointy-stick.com>
wrote:
> I'm going to trim your code to what looks like the relevant portion of
> the HTML template, since that's where the easiest solution lies.
>
> On Thu, 2009-01-08 at 02:02 -0800, Praveen wrote:
>
> [...]
>
>
>
> > list_listing.html
>
> > <div id="leftpart">
> > <h3>Sight Seeings</h3>
> > <ul>
> > {%if listing_result %}
> > {% for n in listing_result %}
> > <li><a href="{{n.id}}">{{n.list_channel}}</a></li>
> > {% endfor %}
> > {% else %}
> > <p>not available</p>
> > {% endif %}
> > </ul>
> > </div>
>
> [...]
>
> > I am displaying Listing_channels and Listing on same page. if some one
> > click on any Listing_channels the corresponding Listing must display
> > on same page. that is why i am also sending the Listing_channels
> > object to list_listing.html page. if some one click first time on
> > Listing_channels it shows the
> > urlhttp://127.0.0.1:8000/category/listing_view/1/
> > but second time it appends 1 at the end and the url becomes
> >http://127.0.0.1:8000/category/listing_view/1/1
>
> The above code fragment is putting an element in the template that looks
> like
>
> <a href="1">...</a>
>
> That is a relative URL reference and will be relative to the URL of the
> current page (which is .../category/listing_view/1/). In other words, it
> will be appended to that URL. One solution is to change the relative
> reference to look like
>
> <a href="../1">...</a>
>
> or, in template language:
>
> <li><a href="../{{n.id}}">{{n.list_channel}}</a></li>
>
> That assumes you will only be displaying this template
> as ..../listing_view/1/ (or with a different number as the final
> component), since it will *always* remove the final component and
> replace it with the id value.
>
> The alternative, which is a little less fragile, is to use the "url"
> template tag to include a URL that goes all the way back to the hostname
> portion. You could write
>
> <li><a href="
> {% url mysite.library.views.listing_view n.id %}
> ">{{n.list_channel}}</a></li>
>
> (I've put in some line breaks just to avoid unpleasant line-wrapping).
> The {% url ... %} portion will return "/category/listing_view/1/" -- or
> whatever the right n.id value is -- which will always be correct.
>
> Have a read
> ofhttp://docs.djangoproject.com/en/dev/ref/templates/builtins/#urlif
> you're not familiar with the URL tag.
>
> Regards,
> Malcolm
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