Shouldn't that be os.path.abspath(os.path.dirname(__file__)) instead just in case the .py file is executed with a relative path?
And Bobby, I would instead use the Sites framework to compute the URL of the site, not rely on a local folder name. Erik On 23.09.2008, at 0:51, Plamen Dragozov wrote: > > From inside a python module: > os.path.dirname(__file__) > > Best, > Plamen Dragozov > > Bobby Roberts wrote: >> >> On Sep 22, 5:05 pm, Jarek Zgoda <[EMAIL PROTECTED]> wrote: >> >>> os.path.dirname() >>> >> >> >> Thanks. The main problem is that i have to dynamically get the url >> i'm at so i can pass to that function ( Python returns that i'm >> missing 1 argument and I don't know how to dynamically pass that in.) >>> >> > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
