From inside a python module: os.path.dirname(__file__) Best, Plamen Dragozov
Bobby Roberts wrote: > > On Sep 22, 5:05 pm, Jarek Zgoda <[EMAIL PROTECTED]> wrote: > >> os.path.dirname() >> > > > Thanks. The main problem is that i have to dynamically get the url > i'm at so i can pass to that function ( Python returns that i'm > missing 1 argument and I don't know how to dynamically pass that in.) > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
