i used that for mine and it always worked! Mine was for a list of child records by date, but child.objects.all()[0] always gave me the most recent object.
J On Sep 2, 7:23 am, mwebs <[EMAIL PROTECTED]> wrote: > Hello, > > I want to perform a lookup an getting the object with the highest > integer value. > The Model looks something like this: > > MyModel: > name = .... > number = models.PositiveIntegerField() > > class Meta: > ordering = [-number] > > So I figured out this: > > highest = MyModel.objects.all()[0] > > Is there another, more elegant way like: highest = > MyModel.object.filter(max(number)), so that I dont have to add the > ordering-attribute in the medta-class? > > Thanks, > Toni --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
