Oh thanks, I think I have overlooked it :-)
On 2 Sep., 16:35, Jarek Zgoda <[EMAIL PROTECTED]> wrote: > Wiadomość napisana w dniu 2008-09-02, o godz. 16:23, przez mwebs: > > > > > > > Hello, > > > I want to perform a lookup an getting the object with the highest > > integer value. > > The Model looks something like this: > > > MyModel: > > name = .... > > number = models.PositiveIntegerField() > > > class Meta: > > ordering = [-number] > > > So I figured out this: > > > highest = MyModel.objects.all()[0] > > > Is there another, more elegant way like: highest = > > MyModel.object.filter(max(number)), so that I dont have to add the > > ordering-attribute in the medta-class? > > Sure, you can always specify ordering using order_by(). Ordering > defines default ordering, where no ordering is specified. > > -- > We read Knuth so you don't have to. - Tim Peters > > Jarek Zgoda, R&D, Redefine > [EMAIL PROTECTED] --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
