Malcolm Tredinnick a écrit :
So the solution is :
In views.py :
user_skill = user.userskill_set.all().select_related()
results = [{'domain': o.name.domain, 'item': o} for o in user_skill]
(exactly as said by Malcolm)
And in the template :
> {% regroup results by domain as domain_list %}
> {% for d in domain_list %}
> <li>{{ d.grouper }}
> <ul>
> {% for item in d.list %}
> <li>...</li>
> {% endfor %}
> </ul>
> </li>
> {% endfor %}
The only change I made was :
{% regroup results|dictsort:"domain.name" by domain as domain_list %}
otherwise, regroup was not always correct.
and a small notice, to access values of the list, it is by using
item.item.<name_of_your_field> : ex : item.item.name
> That looks, to my eye at least, a bit neater than the original solution,
> too. You *might* (completely untested) be able to get away with making
> your results list be:
>
> results = list(user_skill)
> results.sort(key=lambda x: x.getattr('domain').name))
>
> and then grouping by "domain.name", but I'm not 100% certain that will
> work.
I did not test this one - I keep it in mind anyway :)
Thanks a lot for your help Malcom !
Nicolas
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