On Tue, 2008-02-12 at 11:13 +0100, Nicolas Steinmetz wrote:
> Malcolm Tredinnick a écrit :
[...]
>
> > <ul>
> > {% for item in user_skill %}
> > {% ifchanged %}
> > {% ifnotequal forloop.counter 1 %}
> > </ul></li>
> > {% endifnotequal %}
> > <li>{{ item.name.domain }}
> > <ul>
> > {% endifchanged %}
> > <li class="{{ item.level }}">...</li>
> > {% endfor %}
> > </ul>
> > </li>
> > </ul>
[...]
> At code level, it looks great but one bug. The first domain is repeated
> twice whereas for the rest it works like a charm. I will try to see if
> it"s a grouping issue or a template one.
Aah, bother. Yeah, that's a consequence of the ifchanged tag: it
tests against the previous content and since the first time we
don't include "</ul></li>" and the second time we do, it's
considered to have changed. I think I've fallen for that trick
before, now that I think about it. It's going to be fiddly to
work around.
Okay, so maybe this approach is not going to work and we need to look at
the regroup approach. This means you need to create a list of
dictionaries, where each dictionary has, say, a "domain" key and an
"item" key. Something like
results = [{'domain': o.name.domain, 'item': o}
for o in user_skill]
results.sort(key=lambda x: x['domain'])
The last step is important, because regroup only works if the original
list of dictionaries is sorted by the thing you're going to be grouping
by. Then, in your template, you can do:
{% regroup results by domain as domain_list %}
{% for d in domain_list %}
<li>{{ d.grouper }}
<ul>
{% for item in d.list %}
<li>...</li>
{% endfor %}
</ul>
</li>
{% endfor %}
That looks, to my eye at least, a bit neater than the original solution,
too. You *might* (completely untested) be able to get away with making
your results list be:
results = list(user_skill)
results.sort(key=lambda x: x.getattr('domain').name))
and then grouping by "domain.name", but I'm not 100% certain that will
work.
Regards,
Malcolm
--
Atheism is a non-prophet organization.
http://www.pointy-stick.com/blog/
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