Hi,
Do you hire contract based python/django freelancer?
I can help you in this and related tasks
Best,
Karan Sahu
On Monday, July 6, 2020, Clive Bruton <cl...@indx.co.uk> wrote:
> I am struggling with getting kwarg values into a queryset filter:
>
> class UsersItemsView(ListView):
> template_name = 'testapp/user_item_list.html'
>
> def get_queryset(self, **kwargs):
> print('kwargs-userlist')
> print(kwargs)
> #return Item.objects.filter(user__username='clive')
> #return Item.objects.filter(user__id=2)
> return Item.objects.filter(user__id=kwargs['userlist'])
>
> def dispatch(self, *args, **kwargs):
> print('kwargs-userlist')
> print(kwargs['userlist'])
> return super(UsersItemsView, self).dispatch(*args, **kwargs)
>
>
> On dispatch, I can see the value for "kwargs['userlist']" printed in the
> terminal.
>
> But, the queryset returns an error:
>
> Exception Type: KeyError
> Exception Value: 'userlist'
>
> I understand this to mean that the key 'userlist' is not in kwargs, and
> this is confirmed if I "print(kwargs)" inside the get_queryset
>
> If I use the hard-coded filters, commented-out above
> ("user__username='clive'", "user__id=2"), I get the result (from the
> template) that I expect.
>
> So, how do I get the "kwargs['userlist']" passed to the queryset?
>
>
> Thanks
>
>
> -- Clive
>
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