First of all, this is a terrible idea. You should fix up graphobject in your
view to do what you want, not try to massage it in your template.
Second, you can’t use template tags inside a template. That’s not how it works
at all.
Third, you are not the first to have this terrible idea. You can search the
web and find many examples of people “solving” this non-problem.
- Peter of the Norse
> On Apr 20, 2018, at 7:49 AM, Bill Torcaso <torcasob...@gmail.com> wrote:
>
>
> I an new-ish to Django, and I ask this to hear from more experienced users
> whether this would work at all, and whether it would be considered a good or
> bad practice.
>
> Goal: given an object and an integer index, retrieve the sub-object at that
> index within the incoming object.
>
> Method: Write a custom tag. Provide the tag with the larger object, and the
> integer index. Return the sub-object at that index (or whatever field(s) are
> needed).
>
> Usage:
>
> {% for i in metarange %}
> {% graphobject_get_by_index graphobject {{ i }} %}
> {% endfor %}
>
>
> In this particular case, there is an issue about whether the sub-object can
> be null, for some definition of null. There are various ways to deal with
> that.
>
> Again, I am new-ish to Django. Is there a similar approach in which
> 'get_by_index' is a method on class Graphobject, such that this would work?
>
> {% graphobject.get_by_index {{ i }} %}
>
> Thanks for any explanation about these approaches.
>
>
>> On Thursday, April 19, 2018 at 12:01:37 PM UTC-4, shaw...@gmail.com wrote:
>> I am currently working on django.
>>
>> I have a list of values which stored in 'graphobject', and 'metarange' is
>> defined as range(0,59). In that case, how could I use numbers as argument to
>> display the value stored in graphobject? I tried using following codes but
>> it doesn't work
>>
>>
>>
>> {% for i in metarange %}
>> {% if graphobject.i != '' %}
>> {{ graphobject.i }}
>> {% endif %}
>> {% endfor %}
>>
>>
>> Please tell me how could I do this?
>>
>
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