You have a list of values. Use the Pythonic way to iterating over a list,
which does not involve using indices.
{% for o in graphobject %}
{{ o }}<br />
{{ o.subfield }}
{% endfor %}
From: django-users@googlegroups.com [mailto:django-users@googlegroups.com] On
Behalf Of Bill Torcaso
Sent: Friday, April 20, 2018 8:50 AM
To: Django users
Subject: Re: Use self-increasing arguments in numeric for-loop in Django
I an new-ish to Django, and I ask this to hear from more experienced users
whether this would work at all, and whether it would be considered a good or
bad practice.
Goal: given an object and an integer index, retrieve the sub-object at that
index within the incoming object.
Method: Write a custom tag. Provide the tag with the larger object, and the
integer index. Return the sub-object at that index (or whatever field(s) are
needed).
Usage:
{% for i in metarange %}
{% graphobject_get_by_index graphobject {{ i }} %}
{% endfor %}
In this particular case, there is an issue about whether the sub-object can be
null, for some definition of null. There are various ways to deal with that.
Again, I am new-ish to Django. Is there a similar approach in which
'get_by_index' is a method on class Graphobject, such that this would work?
{% graphobject.get_by_index {{ i }} %}
Thanks for any explanation about these approaches.
On Thursday, April 19, 2018 at 12:01:37 PM UTC-4,
shaw...@gmail.com<mailto:shaw...@gmail.com> wrote:
I am currently working on django.
I have a list of values which stored in 'graphobject', and 'metarange' is
defined as range(0,59). In that case, how could I use numbers as argument to
display the value stored in graphobject? I tried using following codes but it
doesn't work
{% for i in metarange %}
{% if graphobject.i != '' %}
{{ graphobject.i }}
{% endif %}
{% endfor %}
Please tell me how could I do this?
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