That’s a great idea. How do you do that programmatically? From: django-users@googlegroups.com [mailto:django-users@googlegroups.com] On Behalf Of "????????? ????????? (roboslone)" Sent: Monday, August 7, 2017 4:32 PM To: django-users@googlegroups.com Subject: Re: Django Python OSError No such file or directory but file exists
You can wait for subprocess to finish and not rely on time.sleep. On 7 Aug 2017, at 23:57, Ronaldo Bahia <rona...@jobconvo.com<mailto:rona...@jobconvo.com>> wrote: Turns out unoconv takes 2 seconds to perform the file conversion. So after the file conversion, I had to set time.sleep(3) before upload a file to S3. And after 1 week I got this working using variables. Thanks Ronaldo Bahia +55 11 3280 6971 +55 11 963 622 581 Materiais gratuitos para o RH: - ROI - Melhorando Indicadores no RH<http://blog.jobconvo.com/post/110644747055/o-impacto-das-entrevistas-virtuais-no-recrutamento?from=email> - Manual do Recrutador Moderno<http://blog.jobconvo.com/post/108666785355/manual-do-recrutador-moderno?from=email> 2017-08-07 17:17 GMT-03:00 Ronaldo Bahia <rona...@jobconvo.com<mailto:rona...@jobconvo.com>>: I don't know why but if I set the string ("cv.pdf"), it process just fine. If I use a variable instead, it doesn't. Here is the working code: # convert to PDF env = os.environ.copy() env['HOME'] = '/tmp' subprocess.Popen(["unoconv","-f", "pdf", "-o", "cv.pdf","%s" % (file_in)], env = env) # Define S3 path resume_path = 'resumes/%s/' % str(date.today()) # key is the S3 file name key = '%s%s' % (resume_path, file_out) # delete local file subprocess.call("rm -f %s" % user_cv_file, shell=True) # update the new file format user_cv.resume = key user_cv.save() # S3 Connection conn = S3Connection(settings.AWS_ACCESS_KEY_ID, settings.AWS_SECRET_ACCESS_KEY) bucket_out = Bucket(conn, settings.AWS_STORAGE_BUCKET_NAME) k_out = Key(bucket=bucket_out, name=user_cv.resume) # Upload to S3 k_out.set_contents_from_filename('cv.pdf') k_out.make_public() # deleta o arquivo localmente subprocess.call("rm -f cv.pdf", shell=True) Ronaldo Bahia +55 11 3280 6971<tel:(11)%203280-6971> +55 11 963 622 581 Materiais gratuitos para o RH: - ROI - Melhorando Indicadores no RH<http://blog.jobconvo.com/post/110644747055/o-impacto-das-entrevistas-virtuais-no-recrutamento?from=email> - Manual do Recrutador Moderno<http://blog.jobconvo.com/post/108666785355/manual-do-recrutador-moderno?from=email> 2017-08-07 8:16 GMT-03:00 "Александр Христюхин (roboslone)" <robosl...@gmail.com<mailto:robosl...@gmail.com>>: Well, yeah, you're using local path basically. And you should NEVER use .split('/')[-1] to determine file basename, take a look at os.path module instead. But that's not the point. You should try to use absolute path, I believe it would do the trick. On 4 Aug 2017, at 17:49, Ronaldo Bahia <rona...@jobconvo.com<mailto:rona...@jobconvo.com>> wrote: the method is called in a def post() within a class view: user_cv = CandidateCV.objects.get(user=request.user) user_cv_file = str(user_cv.resume).split('/')[-1] s3upload(user_cv_file) The file is converted from doc to pdf in server project folder, where manage.py is. So probably there is no absolute path. How can I solve it? Thanks Ronaldo Bahia +55 11 3280 6971<tel:(11)%203280-6971> +55 11 963 622 581 Materiais gratuitos para o RH: - ROI - Melhorando Indicadores no RH<http://blog.jobconvo.com/post/110644747055/o-impacto-das-entrevistas-virtuais-no-recrutamento?from=email> - Manual do Recrutador Moderno<http://blog.jobconvo.com/post/108666785355/manual-do-recrutador-moderno?from=email> 2017-08-03 1:36 GMT-03:00 "Александр Христюхин (roboslone)" <robosl...@gmail.com<mailto:robosl...@gmail.com>>: Hi, Are you sure s3file contains absolute path? I can't see where s3upload is being called. Also, you might wanna use os.remove instead of calling subprocess. You also might wanna check out PEP-8 and Sphinx for your docstrings. On 2 Aug 2017, at 02:28, Ronaldo Bahia <rona...@jobconvo.com<mailto:rona...@jobconvo.com>> wrote: Hi everyone, can you help me? Thanks in advance Thread: https://stackoverflow.com/questions/45449102/django-python-oserror-no-such-file-or-directory-but-file-exists Code: down votefavorite<https://stackoverflow.com/questions/45449102/django-python-oserror-no-such-file-or-directory-but-file-exists> I'm converting doc and docx files to pdf in the server using unoconv with LibreOffice. And I need to upload to S3 the converted file. I can convert with success the files and I can see them in the server. But when I try to upload the pdf, I get the error. What am I missing? Thanks in advance This works just fine: import subprocess from boto.s3.connection import S3Connection, Bucket, Key def doc_to_pdf(user): ''' Convert doc or docx to PDF. parameter user: is a request.user Usage: doc_to_pdf(self.request.user): ''' user_cv = CandidateCV.objects.get(user=user) user_cv_file = str(user_cv.resume).split('/')[-1] # tem que ser PDF user_cv_filetype = user_cv_file.split('.')[-1] if not user_cv_filetype in settings.PDF_FILE_TYPE: # Se não for PDF file_in = user_cv.resume.url file_name = file_in.split('/')[-1] # download urllib.request.urlretrieve(file_in, file_name) file_out = user_cv_file.split('.')[0] + '.pdf' # converte para PDF env = os.environ.copy() env['HOME'] = '/tmp' subprocess.Popen(["unoconv","-f", "pdf", "%s" % (file_in)], env = env) # Define a path para salvar o documento na S3 resume_path = 'resumes/%s/' % str(date.today()) # key é o nome do arquivo na S3 key = '%s%s' % (resume_path, file_out) # deleta o arquivo localmente subprocess.call("rm -f %s" % user_cv_file, shell=True) # Salva o novo formato no banco user_cv.resume = key user_cv.save() This is the code in which I get the error in line: k_out.set_contents_from_filename(s3file) def s3upload(s3file): # Conecta na AWS S3 conn = S3Connection(settings.AWS_ACCESS_KEY_ID, settings.AWS_SECRET_ACCESS_KEY) bucket_out = Bucket(conn, settings.AWS_STORAGE_BUCKET_NAME) k_out = Key(bucket=bucket_out, name=s3file) # Define a path para salvar o documento na S3 resume_path = 'resumes/%s/' % str(date.today()) # key é o nome do arquivo na S3 key = '%s%s' % (resume_path, s3file) k_out.key = key # Salva na AWS S3 k_out.set_contents_from_filename(s3file) k_out.make_public() # deleta o arquivo localmente subprocess.call("rm -f %s" % s3file, shell=True) -- You received this message because you are subscribed to the Google Groups "Django users" group. 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