I don't know why but if I set the string ("cv.pdf"), it process just fine.
If I use a variable instead, it doesn't.
Here is the working code:
# convert to PDF
env = os.environ.copy()
env['HOME'] = '/tmp'
subprocess.Popen(["unoconv","-f", "pdf", "-o", "cv.pdf","%s" %
(file_in)], env = env)
# Define S3 path
resume_path = 'resumes/%s/' % str(date.today())
# key is the S3 file name
key = '%s%s' % (resume_path, file_out)
# delete local file
subprocess.call("rm -f %s" % user_cv_file, shell=True)
# update the new file format
user_cv.resume = key
user_cv.save()
# S3 Connection
conn = S3Connection(settings.AWS_ACCESS_KEY_ID,
settings.AWS_SECRET_ACCESS_KEY)
bucket_out = Bucket(conn, settings.AWS_STORAGE_BUCKET_NAME)
k_out = Key(bucket=bucket_out, name=user_cv.resume)
# Upload to S3
k_out.set_contents_from_filename('cv.pdf')
k_out.make_public()
# deleta o arquivo localmente
subprocess.call("rm -f cv.pdf", shell=True)
*Ronaldo Bahia*
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+55 11 963 622 581
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2017-08-07 8:16 GMT-03:00 "Александр Христюхин (roboslone)" <
robosl...@gmail.com>:
> Well, yeah, you're using local path basically. And you should NEVER use
> .split('/')[-1] to determine file basename, take a look at os.path module
> instead.
>
> But that's not the point. You should try to use absolute path, I believe
> it would do the trick.
>
> On 4 Aug 2017, at 17:49, Ronaldo Bahia <rona...@jobconvo.com> wrote:
>
> the method is called in a def post() within a class view:
>
> user_cv = CandidateCV.objects.get(user=request.user)
> user_cv_file = str(user_cv.resume).split('/')[-1]
> s3upload(user_cv_file)
>
> The file is converted from doc to pdf in server project folder, where
> manage.py is.
> So probably there is no absolute path.
>
> How can I solve it?
>
>
> Thanks
> *Ronaldo Bahia*
> +55 11 3280 6971 <(11)%203280-6971>
> +55 11 963 622 581
>
> *Materiais gratuitos para o RH:*
> - ROI - Melhorando Indicadores no RH
> <http://blog.jobconvo.com/post/110644747055/o-impacto-das-entrevistas-virtuais-no-recrutamento?from=email>
> - Manual do Recrutador Moderno
> <http://blog.jobconvo.com/post/108666785355/manual-do-recrutador-moderno?from=email>
>
> 2017-08-03 1:36 GMT-03:00 "Александр Христюхин (roboslone)" <
> robosl...@gmail.com>:
>
>> Hi,
>>
>> Are you sure s3file contains absolute path? I can't see where s3upload is
>> being called.
>>
>> Also, you might wanna use os.remove instead of calling subprocess.
>> You also might wanna check out PEP-8 and Sphinx for your docstrings.
>>
>> On 2 Aug 2017, at 02:28, Ronaldo Bahia <rona...@jobconvo.com> wrote:
>>
>> Hi everyone, can you help me?
>> Thanks in advance
>>
>> Thread: https://stackoverflow.com/questions/45449102/django-
>> python-oserror-no-such-file-or-directory-but-file-exists
>>
>> Code:
>>
>>
>>
>> down votefavorite
>> <https://stackoverflow.com/questions/45449102/django-python-oserror-no-such-file-or-directory-but-file-exists#>
>>
>> I'm converting doc and docx files to pdf in the server using unoconv with
>> LibreOffice. And I need to upload to S3 the converted file.
>>
>> I can convert with success the files and I can see them in the server.
>>
>> But when I try to upload the pdf, I get the error. What am I missing?
>>
>> Thanks in advance
>>
>> This works just fine:
>>
>> import subprocessfrom boto.s3.connection import S3Connection, Bucket, Key
>> def doc_to_pdf(user):
>> '''
>> Convert doc or docx to PDF.
>>
>> parameter user: is a request.user
>>
>> Usage:
>> doc_to_pdf(self.request.user):
>> '''
>>
>> user_cv = CandidateCV.objects.get(user=user)
>> user_cv_file = str(user_cv.resume).split('/')[-1] # tem que ser PDF
>> user_cv_filetype = user_cv_file.split('.')[-1]
>>
>> if not user_cv_filetype in settings.PDF_FILE_TYPE:
>> # Se não for PDF
>> file_in = user_cv.resume.url
>> file_name = file_in.split('/')[-1]
>> # download
>> urllib.request.urlretrieve(file_in, file_name)
>> file_out = user_cv_file.split('.')[0] + '.pdf'
>>
>> # converte para PDF
>> env = os.environ.copy()
>> env['HOME'] = '/tmp'
>> subprocess.Popen(["unoconv","-f", "pdf", "%s" % (file_in)], env =
>> env)
>>
>> # Define a path para salvar o documento na S3
>> resume_path = 'resumes/%s/' % str(date.today())
>>
>> # key é o nome do arquivo na S3
>> key = '%s%s' % (resume_path, file_out)
>>
>> # deleta o arquivo localmente
>> subprocess.call("rm -f %s" % user_cv_file, shell=True)
>>
>> # Salva o novo formato no banco
>> user_cv.resume = key
>> user_cv.save()
>>
>> This is the code in which I get the error in line:
>> k_out.set_contents_from_filename(s3file)
>>
>> def s3upload(s3file):
>>
>> # Conecta na AWS S3
>> conn = S3Connection(settings.AWS_ACCESS_KEY_ID,
>> settings.AWS_SECRET_ACCESS_KEY)
>> bucket_out = Bucket(conn, settings.AWS_STORAGE_BUCKET_NAME)
>> k_out = Key(bucket=bucket_out, name=s3file)
>>
>> # Define a path para salvar o documento na S3
>> resume_path = 'resumes/%s/' % str(date.today())
>>
>> # key é o nome do arquivo na S3
>> key = '%s%s' % (resume_path, s3file)
>> k_out.key = key
>>
>> # Salva na AWS S3
>> k_out.set_contents_from_filename(s3file)
>> k_out.make_public()
>>
>> # deleta o arquivo localmente
>> subprocess.call("rm -f %s" % s3file, shell=True)
>>
>>
>>
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