On Thu, Feb 21, 2013 at 1:46 PM, Aswani Kumar <aswin.1...@gmail.com> wrote:

> my url pattern
>
> [a-zA-Z0-9]-(?P<nid>\d+).html
>
> urls will be like
>
> news-in-finland-yesterday-festival-3456.html
>
> i want 3456 which is news id.
>
> the regex is correct but not working if i keep it in urls.
> url('^[a-zA-Z0-9]-(?P<nid>\d+).html$', 'tempa'),
>
> please help...
>

why use regex when you can split on - then take the second string and split
on .
>>> url = 'news-in-finland-yesterday-festival-3456.html'
>>> id = url.rsplit('-', 1)[1].split('.')[0]
>>> id
'3456'

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-- 
Joel Goldstick
http://joelgoldstick.com

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