my url pattern [a-zA-Z0-9]-(?P<nid>\d+).html
urls will be like news-in-finland-yesterday-festival-3456.html i want 3456 which is news id. the regex is correct but not working if i keep it in urls. url('^[a-zA-Z0-9]-(?P<nid>\d+).html$', 'tempa'), please help... -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users?hl=en. For more options, visit https://groups.google.com/groups/opt_out.