Okay i think i'm close but i can't figure it out.
I did this:
class ReportingForm_ProduktField(ModelChoiceField):
def label_from_instance(self, obj):
return "My Object #%i" % obj.id
class ReportingForm_Produkt(ModelForm):
Produkt = ReportingForm_ProduktField(Produkte.objects.all())
class Meta:
model = Buchung
I've also tried this:
class ReportingForm_Produkt(ModelForm):
Produkt = forms.ModelChoiceField(ReportingForm_ProduktField,
Produkte.objects.all())
class Meta:
model = Buchung
Could you plz tell me if i'm even close to the solution or maybe even give me a
hint on what I'm doing wrong
Sry but this is rly urgent
. . . . . . . . . . . . . . . . . . . . . . . . . .
Patrick Szabo
XSLT Developer
LexisNexis
Marxergasse 25, 1030 Wien
mailto:patrick.sz...@lexisnexis.at
Tel.: 00431 534521573
Fax: +43 (1) 534 52 - 146
-----Ursprüngliche Nachricht-----
Von: django-users@googlegroups.com [mailto:django-users@googlegroups.com] Im
Auftrag von Tom Evans
Gesendet: Montag, 04. Juli 2011 13:10
An: django-users@googlegroups.com
Betreff: Re: change values in "select list"
On Mon, Jul 4, 2011 at 11:46 AM, Szabo, Patrick (LNG-VIE)
<patrick.sz...@lexisnexis.at> wrote:
> I was afraid somethig like that would come.
> I did read the doc but i don't really understand it :-(
> Could you plz make it a little clearer for me ?!
>
You are using a model form. The model form has a model selection in
it. You want the select to have different labels.
Labels on a model selection field come from the __unicode__ method of
the model, or from the label_from_instance of the model field class.
Model forms allow you to specify the classes to use for each model attribute.
Hence:
Define a new class derived from ModelChoiceField (not called ModelChoiceField).
Add a label_from_instance method to the new class
Configure your ModelForm to use this new field instead of ModelChoiceField
All of this is explained in the docs. Read the docs.
Tom
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