Er, I forgot to add an {% endwith %} at the end. You don't HAVE to use the with tag at all, but it can make things a bit easier.
On 8/11/10 6:18 PM, Joseph Spiros wrote: > You'll want to loop through the objects and print the appropriate > property of the objects that consists of just the name. Here's some > template code that does that, and also separates with commas and "and", > using a serial comma (aka Oxford comma). > > (This assumes that your Filmmaker model has a "name" property/field) > > {% with film.filmmakers.all as filmmakers %}{% for filmmaker in > filmmakers %}{% if filmmakers|length > 2 and not forloop.first %}, {% > endif %}{% if forloop.last and not forloop.first %} and {% endif %}{{ > filmmaker.name }}{% endfor %} > > Hope that helps! > > On 8/11/10 3:53 PM, Wendy wrote: >> Hello, >> I'm just getting started, and I'm returning a many to many object in >> my template: >> >> p>{{ film.filmmakers.all }} >> >> So it's displaying the list: >> >> [<Filmmaker: John Smith>, <Filmmaker: Suzie Brown>] >> >> Can anyone tell me how to return just a string of the names? >> I'm still getting acclimated to python syntax. >> >> Actually in a perfect world, it would be great to concatenate the >> names, and add an 'and' b4 the last one, I imagine this is done >> frequently? >> >> Thanks, >> Wendy >> > -- Joseph Spiros iThink Software joseph.spi...@ithinksw.com +1 (440) 707-6855 -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.