You'll want to loop through the objects and print the appropriate property of the objects that consists of just the name. Here's some template code that does that, and also separates with commas and "and", using a serial comma (aka Oxford comma).
(This assumes that your Filmmaker model has a "name" property/field) {% with film.filmmakers.all as filmmakers %}{% for filmmaker in filmmakers %}{% if filmmakers|length > 2 and not forloop.first %}, {% endif %}{% if forloop.last and not forloop.first %} and {% endif %}{{ filmmaker.name }}{% endfor %} Hope that helps! On 8/11/10 3:53 PM, Wendy wrote: > Hello, > I'm just getting started, and I'm returning a many to many object in > my template: > > p>{{ film.filmmakers.all }} > > So it's displaying the list: > > [<Filmmaker: John Smith>, <Filmmaker: Suzie Brown>] > > Can anyone tell me how to return just a string of the names? > I'm still getting acclimated to python syntax. > > Actually in a perfect world, it would be great to concatenate the > names, and add an 'and' b4 the last one, I imagine this is done > frequently? > > Thanks, > Wendy > -- Joseph Spiros iThink Software joseph.spi...@ithinksw.com +1 (440) 707-6855 -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.