Mmmmm the third case coul be this, for example:
|-------A-------------| |--------------A------------|
----------------------------- --------------------------------------
|B| |-----B----|
If I directly apply (his_diff/my_diff) I think that I'm assuming that A = 2B
and it isn't the case... I need to get my range and her range and deleter
the union between them with a substraction.
range(A) - range(B) 17000s - 13000s
---------------------------- for example: --------------------------- =
0.2352 = 23%
range(A) 17000s
What do you think about? Perhaps I'm mading mistakes and can't understand
your reply. Anyway, thanks for reply :)
Bye!
Álex González
On Fri, Aug 6, 2010 at 02:09, Paulo Almeida <igcbioinformat...@gmail.com>wrote:
> In the third case, I didn't understand why you didn't divide (his_to -
> his_from) / (my_to - my_from). Bearing that in mind, this made sense in my
> head, but analyze it carefully:
>
> def match(mf,mt,hf,ht):
> mydiff = diff_in_seconds(mf,mt)
> if (mf >= hf and mt <= ht) or (mf < hf and mt > ht):
> mydiff = diff_in_seconds(mf,mt)
> hisdiff = diff_in_seconds(hf,ht)
> return min(1, hisdiff / mydiff)
> else:
> case1 = max(0, diff_in_seconds(hf, mt))
> case2 = max(0, diff_in_seconds(mf, ht))
> diff = min(case1, case2)
> return (diff / mydiff)
>
> def diff_in_seconds(d1,d2):
> timedelta = d2 - d1
> return float(timedelta)
>
> print match(0,100,40,90)
>
>
> 2010/8/5 Alexandre González <agonzale...@gmail.com>
>
>> I've develope a "simple" function to calculate the difference between 2
>> dates, and the time that they are interpolated.
>>
>> I need it to: I arrive to a site at a hour (my_from), I go out from the
>> site at a hour (my_to). Some friend arrive at the site at a hour (his_from)
>> and let it at a hour (his_to)
>>
>> If I stay in the site after he arrives and before he goes out, the
>> "probability" of match is 1, if I let the site after he arrives, the
>> probability of match is 0... You can see the samples in the documentation.
>>
>> I need to know if this is a good way to do, and if compare all the kinds
>> of matching (I've found 6). This is the code:
>>
>> def time_match(self, my_from, my_to, his_from, his_to):
>> """
>> I've found 6 general kinds of time matching. It's better to
>> explain it with graphics:
>>
>> (my_from)--A--(my_to)
>> -------------------------
>> (his_from)--B--(his_to)
>> """
>>
>> # |-A-| |-A-|
>> # -------------------- or --------------------
>> # |--B--| |--B--|
>> if my_to < his_from or his_to < my_from:
>> return 0
>>
>> # |--A--|
>> # --------------------
>> # |------B-------|
>> elif my_from >= his_from and my_to <= his_to:
>> return 1
>>
>> # |-----A-------|
>> # --------------------
>> # |-B-|
>> elif my_from < his_from and my_to > his_to:
>> my_diff_to_reuse = diff_in_seconds(my_from, my_to)
>> diff = my_diff_to_reuse - self.diff_in_seconds(his_from,
>> his_to)
>>
>> return (diff / my_diff_to_reuse)
>>
>> # |---A---|
>> # --------------------
>> # |---B---|
>> elif my_from <= his_from and my_to <= his_to:
>> diff = self.diff_in_seconds(his_from, my_to)
>>
>> return (diff / self.diff_in_seconds(my_from, my_to))
>>
>> # |---A---|
>> # --------------------
>> # |---B---|
>> elif my_from >= his_from and my_to >= his_to:
>> diff = self.diff_in_seconds(my_from, his_to)
>>
>> return (diff / self.diff_in_seconds(my_from, my_to))
>>
>> # If I'm here I have a problem
>> return 0
>>
>>
>> def diff_in_seconds(date1, date2):
>> # Initial from: http://www.bytemycode.com/snippets/snippet/304/
>> timedelta = date2 - date1
>> diff = timedelta.days*24*3600 + timedelta.seconds
>>
>> return abs(float(diff))
>>
>> Thanks!
>> --
>> Please, don't send me files with extensions: .doc, .docx, .xls, .xlsx,
>> .ppt and/or .pptx
>> http://mirblu.com
>>
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>
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and/or .pptx
http://mirblu.com
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