I would have rather done something simple like: set(Member.objects.values_list('status', flat=True))
Thanks, Subhranath Chunder. On Thu, Jul 22, 2010 at 12:03 AM, Subhranath Chunder <subhran...@gmail.com>wrote: > I thought you were trying to get: > > I'm expecting only the four distinct records. > > You'll get a ValuesQuerySet or list of dictionaries with redundant keys > this way. > > Thanks, > Subhranath Chunder. > > On Wed, Jul 21, 2010 at 11:40 PM, rmschne <rmsc...@gmail.com> wrote: > >> Member.objects.values('status').order_by('status').distinct() from >> jaymzcd works perfectly. Thanks! >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Django users" group. >> To post to this group, send email to django-us...@googlegroups.com. >> To unsubscribe from this group, send email to >> django-users+unsubscr...@googlegroups.com<django-users%2bunsubscr...@googlegroups.com> >> . >> For more options, visit this group at >> http://groups.google.com/group/django-users?hl=en. >> >> > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.