I thought you were trying to get: I'm expecting only the four distinct records.
You'll get a ValuesQuerySet or list of dictionaries with redundant keys this way. Thanks, Subhranath Chunder. On Wed, Jul 21, 2010 at 11:40 PM, rmschne <rmsc...@gmail.com> wrote: > Member.objects.values('status').order_by('status').distinct() from > jaymzcd works perfectly. Thanks! > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com<django-users%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.