Re: Task to throw away string parts, use joiner and splitter not very successful

[bearophile]

Chris Cain:

From your error message: isForwardRange!Separator
Your separator is a character, which isn't a forward range. Try 
this:
`auto name1 = joiner(nameparts[0 .. $-1], ".");`

But splitting on a char is a common operation, and isn't it more 
efficient than splitting on a string?

Bye,
bearophile