On Tuesday, 31 December 2013 at 20:49:55 UTC, Dfr wrote:
Hello, i have string like "this.is.a.string" and want to throw
away some parts separated by dots, here is first attempt:
name = "this.is.a.string"; // <-- want to make "this.is.a" from
this
auto nameparts = splitter(name, '.');
auto name1 = joiner(nameparts[0 .. $-1], '.');
And got this error: "Error: Result cannot be sliced with []"
So, kinda fixed it (correct way?):
name = "this.is.a.string";
auto nameparts = splitter(name, '.').array;
auto name1 = joiner(nameparts[0 .. $-1], '.');
got this:
Error: template std.algorithm.joiner does not match any
function template declaration. Candidates are:
/usr/include/dmd/phobos/std/algorithm.d(2846):
std.algorithm.joiner(RoR, Separator)(RoR r, Separator sep) if
(isInputRange!RoR && isInputRange!(ElementType!RoR) &&
isForwardRange!Separator && is(ElementType!Separator :
ElementType!(ElementType!RoR)))
Stuck here, thank you for any help.
From your error message: isForwardRange!Separator
Your separator is a character, which isn't a forward range. Try
this:
`auto name1 = joiner(nameparts[0 .. $-1], ".");`
