virtio-user cannot work on 32-bit system as higher 32-bit of the
addr field (64-bit) in the desc is filled with non-zero value
which should not happen for a 32-bit system.
This is a regression bug. For 32-bit system, the first 4 bytes
is the virtual address, with following 8 bytes pointing to
physical addr. With below wrong definition, both virtual address
and lower 4 bytes of physical addr are obtained.
#define VIRTIO_MBUF_ADDR(mb, vq) \
(*(uint64_t *)((uintptr_t)(mb) + (vq)->offset))
Fixes: 25f80d108780 ("net/virtio: fix packet corruption")
Cc: sta...@dpdk.org
Signed-off-by: Jianfeng Tan <jianfeng....@intel.com>
---
drivers/net/virtio/virtqueue.h | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/drivers/net/virtio/virtqueue.h b/drivers/net/virtio/virtqueue.h
index f9e3736..f43ea70 100644
--- a/drivers/net/virtio/virtqueue.h
+++ b/drivers/net/virtio/virtqueue.h
@@ -72,7 +72,8 @@ struct rte_mbuf;
* Return the physical address (or virtual address in case of
* virtio-user) of mbuf data buffer.
*/
-#define VIRTIO_MBUF_ADDR(mb, vq) (*(uint64_t *)((uintptr_t)(mb) +
(vq)->offset))
+#define VIRTIO_MBUF_ADDR(mb, vq) \
+ ((uint64_t)((uintptr_t)(*(void **)((uintptr_t)(mb) + (vq)->offset))))
#else
#define VIRTIO_MBUF_ADDR(mb, vq) ((mb)->buf_physaddr)
#endif
--
2.7.4
