On Fri, Feb 24, 2017 at 11:08:56AM +0000, Kevin Traynor wrote:
> On 02/24/2017 08:48 AM, Zhiyong Yang wrote:
> > vhost removes limit of TX burst size(32 pkts) and supports to make
> > an best effort to transmit pkts.
> >
> > Cc: yuanhan....@linux.intel.com
> > Cc: maxime.coque...@redhat.com
> >
> > Signed-off-by: Zhiyong Yang <zhiyong.y...@intel.com>
> > ---
> > drivers/net/vhost/rte_eth_vhost.c | 24 ++++++++++++++++++++++--
> > 1 file changed, 22 insertions(+), 2 deletions(-)
> >
> > diff --git a/drivers/net/vhost/rte_eth_vhost.c
> > b/drivers/net/vhost/rte_eth_vhost.c
> > index e98cffd..1e1fa34 100644
> > --- a/drivers/net/vhost/rte_eth_vhost.c
> > +++ b/drivers/net/vhost/rte_eth_vhost.c
> > @@ -52,6 +52,7 @@
> > #define ETH_VHOST_QUEUES_ARG "queues"
> > #define ETH_VHOST_CLIENT_ARG "client"
> > #define ETH_VHOST_DEQUEUE_ZERO_COPY "dequeue-zero-copy"
> > +#define VHOST_MAX_PKT_BURST 32
> >
> > static const char *valid_arguments[] = {
> > ETH_VHOST_IFACE_ARG,
> > @@ -434,8 +435,27 @@ eth_vhost_tx(void *q, struct rte_mbuf **bufs, uint16_t
> > nb_bufs)
> > goto out;
> >
> > /* Enqueue packets to guest RX queue */
> > - nb_tx = rte_vhost_enqueue_burst(r->vid,
> > - r->virtqueue_id, bufs, nb_bufs);
> > + if (likely(nb_bufs <= VHOST_MAX_PKT_BURST))
> > + nb_tx = rte_vhost_enqueue_burst(r->vid, r->virtqueue_id,
> > + bufs, nb_bufs);
> > + else {
> > + uint16_t nb_send = nb_bufs;
> > +
> > + while (nb_send) {
> > + uint16_t nb_pkts;
> > + uint16_t num = (uint16_t)RTE_MIN(nb_send,
> > + VHOST_MAX_PKT_BURST);
> > +
> > + nb_pkts = rte_vhost_enqueue_burst(r->vid,
> > + r->virtqueue_id,
> > + &bufs[nb_tx], num);
> > +
> > + nb_tx += nb_pkts;
> > + nb_send -= nb_pkts;
> > + if (nb_pkts < num)
> > + break;
> > + }
>
> In the code above,
> - if the VM does not service the queue, this will spin forever
I don't think that is the case. As soon as the enqueue stops sending a
full burst of (presumably 32) pkts, it will hit the break condition and
quit. If it does send the full burst, it makes good forward progress
until it runs out of packets to send and then quits.
> - if the queue is almost full, it will be very slow
Again, should not be the case. As soon as a full burst is not full
enqueued the logic quits the loop.
/Bruce
