> -----Original Message-----
> From: Wu, Jingjing
> Sent: Monday, October 19, 2015 4:30 PM
> To: Zhang, Helin; dev at dpdk.org
> Cc: Pei, Yulong; Liu, Yong
> Subject: RE: [PATCH 2/2] i40e: Enlarge the number of supported queues
> 
> Hi, helin
> 
> Few comments
> 
> > a/drivers/net/i40e/i40e_ethdev.c b/drivers/net/i40e/i40e_ethdev.c
> > index
> > 4b70588..3bdcaa4 100644
> > --- a/drivers/net/i40e/i40e_ethdev.c
> > +++ b/drivers/net/i40e/i40e_ethdev.c
> > @@ -2240,113 +2240,88 @@ i40e_pf_parameter_init(struct rte_eth_dev
> > *dev)  {
> >     struct i40e_pf *pf = I40E_DEV_PRIVATE_TO_PF(dev->data-
> > >dev_private);
> >     struct i40e_hw *hw = I40E_PF_TO_HW(pf);
> > -   uint16_t sum_queues = 0, sum_vsis, left_queues;
> > +   uint16_t qp_count = 0, vsi_count = 0;
> >
> > -   /* First check if FW support SRIOV */
> >     if (dev->pci_dev->max_vfs && !hw->func_caps.sr_iov_1_1) {
> >             PMD_INIT_LOG(ERR, "HW configuration doesn't support SRIOV");
> >             return -EINVAL;
> >     }
> >
> >     pf->flags = I40E_FLAG_HEADER_SPLIT_DISABLED;
> > -   pf->max_num_vsi = RTE_MIN(hw->func_caps.num_vsis,
> > I40E_MAX_NUM_VSIS);
> > -   PMD_INIT_LOG(INFO, "Max supported VSIs:%u", pf->max_num_vsi);
> > -   /* Allocate queues for pf */
> > -   if (hw->func_caps.rss) {
> > -           pf->flags |= I40E_FLAG_RSS;
> > -           pf->lan_nb_qps = RTE_MIN(hw->func_caps.num_tx_qp,
> > -                   (uint32_t)(1 << hw-
> > >func_caps.rss_table_entry_width));
> > -           pf->lan_nb_qps = i40e_align_floor(pf->lan_nb_qps);
> > -   } else
> > +   pf->max_num_vsi = hw->func_caps.num_vsis;
> > +   pf->lan_nb_qp_max = RTE_LIBRTE_I40E_QUEUE_NUM_PER_PF;
> > +   pf->vmdq_nb_qp_max = RTE_LIBRTE_I40E_QUEUE_NUM_PER_VM;
> > +   pf->vf_nb_qp_max = RTE_LIBRTE_I40E_QUEUE_NUM_PER_PF;
> > +
> Need use the NUM_PER_VF but not NUM_PER_PF
> pf->vf_nb_qp_max = RTE_LIBRTE_I40E_QUEUE_NUM_PER_PF? ==>
> pf->pf->vf_nb_qp_max = RTE_LIBRTE_I40E_QUEUE_NUM_PER_VF;
Yes, you are right. Thank you very much!
I will correct it in the next version.

Helin

> 

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