+1. Seems to fit a RegexUtils.wildcardToRegex type method.
Note that IO has a Wildcard concept already, so ideally it would match
the same schema.
Hen
On Sat, Oct 9, 2010 at 6:13 AM, sebb <seb...@gmail.com> wrote:
> On 9 October 2010 12:33, Stephen Colebourne <scolebou...@joda.org> wrote:
>> No, the wildcard is used for a database search. Find me all names
>> matching "Foo*". This is not for [io].
>
> But where do humans get the idea that * and ? are wildcards?
>
>>
>> The oro code does look reasonable I'd say.
>
> Agreed, it could be adapted for Commons.
>
> However, whether the syntax it supports is universal I don't know.
>
> I think it's a useful addition, but the syntax needs to be carefully
> documented.
>
> And it would be useful if there were versions for different OSes, to
> allow filename matching using the standard for that OS.
>
>> Stephen
>>
>>
>> On 9 October 2010 12:25, sebb <seb...@gmail.com> wrote:
>>> What does the regex represent? A filename?
>>>
>>> If so, then maybe the code belongs in IO rather than Lang.
>>>
>>> Also, filename globbing is not consistent across OSes.
>>>
>>> On 8 October 2010 15:32, Stephen Colebourne <scolebou...@joda.org> wrote:
>>>> Human users enter wildcards * and ? (because regex is too complex). In
>>>> my case, I'm passing it to MongoDB, which needs regex.
>>>>
>>>> Stephen
>>>>
>>>>
>>>> On 8 October 2010 15:10, Paul Benedict <pbened...@apache.org> wrote:
>>>>> Can I get some sense of use case? What would you use it for? Just curious.
>>>>>
>>>>> On Fri, Oct 8, 2010 at 9:06 AM, Stephen Colebourne <scolebou...@joda.org>
>>>>> wrote:
>>>>>> I don't think comons lang has a routine for converting a standard
>>>>>> wildcard string (with * and ?) to a regex.
>>>>>> Here is a first suggestion, although I'm sure it can be improved.
>>>>>>
>>>>>> public Pattern createPattern(String text) {
>>>>>> StringTokenizer tkn = new StringTokenizer(text, "?*", true);
>>>>>> StringBuilder buf = new StringBuilder(text.length() + 10);
>>>>>> buf.append('^');
>>>>>> boolean lastStar = false;
>>>>>> while (tkn.hasMoreTokens()) {
>>>>>> String str = tkn.nextToken();
>>>>>> if (str.equals("?")) {
>>>>>> buf.append('.');
>>>>>> lastStar = false;
>>>>>> } else if (str.equals("*")) {
>>>>>> if (lastStar == false) {
>>>>>> buf.append(".*");
>>>>>> }
>>>>>> lastStar = true;
>>>>>> } else {
>>>>>> buf.append(Pattern.quote(str));
>>>>>> lastStar = false;
>>>>>> }
>>>>>> }
>>>>>> buf.append('$');
>>>>>> return Pattern.compile(buf.toString(), Pattern.CASE_INSENSITIVE);
>>>>>> }
>>>>>>
>>>>>> Other possile conversions would be * and ? to databse wildcards, so
>>>>>> perhaps there is scope for a few related methods here?
>>>>>>
>>>>>> Stephen
>>>>>>
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>>>>>>
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