Human users enter wildcards * and ? (because regex is too complex). In
my case, I'm passing it to MongoDB, which needs regex.
Stephen
On 8 October 2010 15:10, Paul Benedict <pbened...@apache.org> wrote:
> Can I get some sense of use case? What would you use it for? Just curious.
>
> On Fri, Oct 8, 2010 at 9:06 AM, Stephen Colebourne <scolebou...@joda.org>
> wrote:
>> I don't think comons lang has a routine for converting a standard
>> wildcard string (with * and ?) to a regex.
>> Here is a first suggestion, although I'm sure it can be improved.
>>
>> public Pattern createPattern(String text) {
>> StringTokenizer tkn = new StringTokenizer(text, "?*", true);
>> StringBuilder buf = new StringBuilder(text.length() + 10);
>> buf.append('^');
>> boolean lastStar = false;
>> while (tkn.hasMoreTokens()) {
>> String str = tkn.nextToken();
>> if (str.equals("?")) {
>> buf.append('.');
>> lastStar = false;
>> } else if (str.equals("*")) {
>> if (lastStar == false) {
>> buf.append(".*");
>> }
>> lastStar = true;
>> } else {
>> buf.append(Pattern.quote(str));
>> lastStar = false;
>> }
>> }
>> buf.append('$');
>> return Pattern.compile(buf.toString(), Pattern.CASE_INSENSITIVE);
>> }
>>
>> Other possile conversions would be * and ? to databse wildcards, so
>> perhaps there is scope for a few related methods here?
>>
>> Stephen
>>
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