Re: Warning about "mutating the [[Prototype]] of an object" ?

[Andrew Sutherland]

The code should be fixed.  It's my understanding that the existing idiom 
used throughout the Thunderbird tree is still okay to do since the 
prototype chain is created at object initialization time and so there's 
no actual mutation of the chain:

function Application() {
}
Application.prototype = {
  __proto__: extApplication.prototype,
};
Andrew

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