On Sat, 2003-06-28 at 10:03, David selby wrote: > Hello, > > I am writing bash a bash & sed script, it has been going suprisingly > well. I need a loop to count 9 times & the variable n to the count .. > > for n=1 to 9 > .... > next > > kind of thing, but this is not BASIC !! > > My best guess is > > declare -i n=1 > while [ $n < 9 ]; do > ..... > n=$((n+=1)) > done > > All i get is ... > > [EMAIL PROTECTED]:/usr/local/myfiles/dave/websites/kcards$ ./gensite > ./gensite: 9: No such file or directory > > I have defined it as an integer, used the less than operator for > integers, ... errr ... I know its something stupid but I can't crack it .... > > Dave > > PS is there a more ellagent way to do a counted loop as well as a way > that works ? > > > >
$ seq --help Usage: seq [OPTION]... LAST or: seq [OPTION]... FIRST LAST or: seq [OPTION]... FIRST INCREMENT LAST Print numbers from FIRST to LAST, in steps of INCREMENT. <snip> $ for n in `seq 1 9` ; do echo $n ; done 1 2 3 4 5 6 7 8 9 Note the backticks on seq and you should be good to go. regards, Shaun. -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
