Hello,
I am writing bash a bash & sed script, it has been going suprisingly well. I need a loop to count 9 times & the variable n to the count ..
for n=1 to 9 .... next
kind of thing, but this is not BASIC !!
My best guess is
declare -i n=1 while [ $n < 9 ]; do ..... n=$((n+=1)) done
All i get is ...
[EMAIL PROTECTED]:/usr/local/myfiles/dave/websites/kcards$ ./gensite ./gensite: 9: No such file or directory
I have defined it as an integer, used the less than operator for integers, ... errr ... I know its something stupid but I can't crack it ....
Dave
PS is there a more ellagent way to do a counted loop as well as a way that works ?
You could mod this to increment:
#!/bin/sh let count=10 echo -e "Colour test\n" while [ $count -gt 0 ] ; do echo -ne \ "\e[40m\e[30m####"\ "\e[41m\e[31m####"\ "\e[42m\e[32m####"\ "\e[43m\e[33m####"\ "\e[44m\e[34m####"\ "\e[45m\e[35m####"\ "\e[46m\e[36m####"\ "\e[47m\e[37m####"\ "\e[49m\e[39m"\ "\e[1m"\ "\e[40m\e[30m####"\ "\e[41m\e[31m####"\ "\e[42m\e[32m####"\ "\e[43m\e[33m####"\ "\e[44m\e[34m####"\ "\e[45m\e[35m####"\ "\e[46m\e[36m####"\ "\e[47m\e[37m####"\ "\e[49m\e[39m"\ "\e[0m\n" let count=count-1 done
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