On Thu, Oct 13, 2005 at 08:18:05AM -0700, Freddy Freeloader wrote:
> b=${a/23/BB}
>
> echo "b = $b"
>
> Now the ABS guide says that where I'm setting b it should be
> substituting BB for 23. It also says that the output of 'echo "b - $b"'
> should be: b = BB35Well, it's taking whatever the value of $a is, and replacing 23 with BB. You didn't specify the value of $a before you run that substitution; what is it? -- Stephen R. Laniel [EMAIL PROTECTED] +(617) 308-5571 http://laniels.org/ PGP key: http://laniels.org/slaniel.key
signature.asc
Description: Digital signature
