LOL. I knew immediately after I sent that not saying that "a" was unset
was a mistake. Sorry.
Stephen R Laniel wrote:
On Thu, Oct 13, 2005 at 08:18:05AM -0700, Freddy Freeloader wrote:
b=${a/23/BB}
echo "b = $b"
Now the ABS guide says that where I'm setting b it should be
substituting BB for 23. It also says that the output of 'echo "b - $b"'
should be: b = BB35
Well, it's taking whatever the value of $a is, and replacing
23 with BB. You didn't specify the value of $a before you
run that substitution; what is it?
--
To UNSUBSCRIBE, email to [EMAIL PROTECTED]
with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
