Hello I have a problem with a simple operation. I cannot open a XML-File!!!
This code: public class Task3 { public static void main(String[] args) throws IOException { int laenge = 0; try{ laenge = args[0].length(); } catch (ArrayIndexOutOfBoundsException e){ System.out.println("Usage: java Task3 <file> "); System.exit(0);} if(laenge > 1) { File fil = new File(args[0]); Parser par = new Parser(fil); } } } // calls this Object: class Parser { FileReader file1; public Parser(File f, Vector v) { try { file1 = new FileReader(f); }catch (FileNotFoundException e){ System.out.println("File access error"); System.out.println(e.toString()); } ............ } } With this code it is imposible to open any file with a .xml - suffix. I can but any kind of ascii-file. Accept for the case, if I call the file with its full path. But how is this possible? Can anybody help me? Gruss Christian -- Christian Stalp Wiesbaden / Germany [EMAIL PROTECTED] ICQ 23091256 -----------------www.stalp.de----------------------- -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]