Greg,
By two meshes matching do you mean there is no hanging nodes? Or they come
from the same Triangulation object (and same DoFHandler object, for that matter)?
I meant that a face of the triangulation used for the "old" slab exactly
matches a face of the triangulation used for the "new" slab. I think that
matches your first option above.
(Adding one level of refinement won't make this much more difficult. But using
two completely unrelated triangulations does.)
The key to what you want to do is to find matching face pairs where you move
from one slab to the next. Since they are geometrically at the same location,
you basically end up with the same kind of terms that you also need to
assemble when doing discontinuous Galerkin methods.
Best
W.
--
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Wolfgang Bangerth email: bange...@colostate.edu
www: http://www.math.colostate.edu/~bangerth/
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