On Wednesday, August 29, 2018 at 3:51:35 PM UTC+2, Jean-Paul Pelteret wrote: > > Hi Kendra, > > > Thank you, Jean-Paul, for the hint. Unfortunately this is not really > what I am looking for. I found a solution (that I don't like) by iterating > through two meshes on different levels simultaneously. Once I find a good > solution I will post it here and link to the code. > > I read your question again and I recognise that I didn’t interpret it > correctly at all. > > Do I understand correctly that your meshes are identical up to a certain > level n_c and then in the one mesh undergoes further refinement? I think > that if you iterate over all cells on levels [0,n_c) then they should be > traversed identically (this would require some confirmation though). What > you could then do for each “coarse cell” (potentially an inactive one) on > your second grid is to traverse all of its children until you reach the end > of the child tree - those would be your active child cells. If you’re not > needing to sweep up and down the child tree then you could cache the > correspondence between the coarse cell on mesh 1 and the active children > cells on mesh 2. > > Best, > J-P
This is exactly what I am doing. Works. :-) Konrad -- The deal.II project is located at http://www.dealii.org/ For mailing list/forum options, see https://groups.google.com/d/forum/dealii?hl=en --- You received this message because you are subscribed to the Google Groups "deal.II User Group" group. To unsubscribe from this group and stop receiving emails from it, send an email to dealii+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
