Hannu E K Nevalainen wrote: > $ echo ' a b / c d e ' | \ > sed -e 's/ *\(.*\) *\/ *\(.*\) */.\1.\2./' > .a b .c d e . > > I want the output to be '.a b.c d e.' - that is; strip out the trailing > spaces. > > HOW do I achieve that? ( \s = any ws, \S = any non ws ) > > Obviously \(.*\) grabs/includes the last space. My brain has stoppped > working, so right now I can't work around that :-I
Personally, I can't stand the "basic" style regexps that sed uses, and I prefer perl-compatible. You can use the non-greedy modifier, for example: command | perl -pe 's!^ +(.*) +/ +(.*?) +$!.\1.\2.!' Brian -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
