Greetings,
This isn't directly a cygwin question, but hopefully somebody has a
suggestion or a new topic I should search on:
I have a working C program created with GCC 2.95.2-6 and Cygwin
dll 1.1.7. I realize both of these are a little old, but I think
I have a conceptual problem rather than a version issue.
I want to find the current directory that the executable file is in,
so I can open a text file in the same directory. The executable
is on the k drive, but my code doesn't return the correct path:
/* Begin code sample */
main()
{
FILE *testfile;
char buffer[100];
int size = 100;
testfile = fopen("c:\\windows\\desktop\\test.txt","w");
getcwd(buffer,size);
fprintf(testfile,"buffer = %s\n",buffer);
}
/* End code sample */
which returns:
buffer = /cygdrive/c/WINDOWS/DESKTOP
I am probably using the wrong function or possibly need to look
at a Windows-based group of functions?
TIA for any ideas.
Francis R. Harvey III
WB303, x3952
[EMAIL PROTECTED]
VB programmers know the wisdom of Nothing
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